1. main()
{
extern int i;
i=20;
printf("%d",i);
}
2. main()
{
int i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}
3. main()
{
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
}
4. main()
{
int i=3;
switch(i)
{
default:printf("zero");
case 1: printf("one");
break;
case 2:printf("two");
break;
case 3: printf("three");
break;
}
}
5. main()
{
printf("%x",-1<<4);
}
Find the answers and check your answers on tomorrow(23-07-2011)
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